Answer to Question #181489 in Physical Chemistry for NNN

Question

How many grams of NaCl should be weighed to prepare 1.00 L of 601 ppm solution of Na⁺? 

Answer 1

1L = 1000g

NaCl -> Na⁺ + Cl^-

Mole ratio is 1:1

ppm = ( m solute/m water) × 10⁶

M solute = (ppm × m water)/10⁶

= (601 × 1000)/10⁶

= 0.601g

= 0.601g/23.0g

=0.02613 moles Na+

Now use sodium chloride's molar mass to determine how much you need

0.02613moles × 58.44 g

=1.527 g NaCl