Answer to Question #180282 in Physical Chemistry for Shishir

Question

When 0.935g of a fuel underwent complete combustion in excess of oxygen, the increase of temperature of water in a calorimeter containing 1.365g of water was 2.40⁰ C. calculate the higher calorific value of the fuel, if the water equivalent of calorimeter, etc. is 135g.

Answer 1

HCV = (W1 + W2) × S × ∆T )/M

= (1.365 + 135) 10^-3 × 4.187×2.4/0.935 × 10^-3

= 1465.566kJ/KG