Question #17913
Calculate the wavelength, in metres, of a photon capable of exciting an electron in He+ from the ground state to n=4... Someone please tell me the right answer urgently :( ?
Expert's answer
Energy levels for the hydrogen-like He+ are given by
E(n) = -Z2*R/n2, where Z = 2;
Energy of an absorbed photon between the levels n=1 and m=4
E(m,n) = Z2*R*(1/n2 - 1/m2)
We will take R = 10973731.6 m-1, Rydberg constant for H, in reciprocal meters.
Photon wavelength
lambda = h*c/E = 1/Z2*R*(1/n2 - 1/m2)) = 1/(22*10,973,731.6 m-1*(1/12 - 1/42)) = 3.746*10-8 m
Answer: 3.746*10-8 meters
E(n) = -Z2*R/n2, where Z = 2;
Energy of an absorbed photon between the levels n=1 and m=4
E(m,n) = Z2*R*(1/n2 - 1/m2)
We will take R = 10973731.6 m-1, Rydberg constant for H, in reciprocal meters.
Photon wavelength
lambda = h*c/E = 1/Z2*R*(1/n2 - 1/m2)) = 1/(22*10,973,731.6 m-1*(1/12 - 1/42)) = 3.746*10-8 m
Answer: 3.746*10-8 meters
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#340153 on Dec 2023
#340153 on Dec 2023