Answer to Question #178320 in Physical Chemistry for glicelyn arisco

Question

The decomposition of magnesium carbonate (MgCO3) forms 18 grams of magnesium oxide (MgO) in an experiment. The theoretical yield is known to be 21 grams. What is the percentage yield of magnesium oxide (MgO)?

Answer 1

In question, we are given,

Actual yield of magnesium oxide = 15.00 g and Theoretical yield of magnesium oxide = 19.00 g

Actual yield: It is the actual amount produced in the experiment.

Actual yield is obtained by doing an experiment in the lab.

Theoretical yield: It is the maximum amount of product that can be produced from the chemical reaction.

Theoretical yield is obtained from stoichiometric calculation.

The formula for finding percent yield is

% yield = Actual yield / Theoretical yield * 100

% yield = 15.00g / 19.00g * 100

= 0.78947 * 100

= 78.947 %

In question, we are given actual yield and theoretical yield in 4 significant figures, so our final answer must also be in 4 significant figures.

Therefore the %yield of magnesium oxide is 78.95%