Question #177970

The first-order rate constant for the decomposition of N2O5 to NO2 and O2 at 70 °C is 5.3 × 10–3 s–1. Suppose we start with 0.500 mol of N2O5(g) in a 0.700 L container, how many moles of N2O5 will remain after 1.5 min?



1
Expert's answer
2021-04-05T07:58:00-0400



ln(A0At)=ktln(\frac{A_0}{A_t})=kt


ln(A0At)=5.3×103×1.5×60ln(\frac{A_0}{A_t})=5.3×10^{-3}×1.5×60


ln(A0At)=0.447ln(\frac{A_0}{A_t})=0.447


At=(0.500e0.447)=0.31molesA_t=(\frac{0.500}{e^{0.447}})=0.31 moles


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