Question

If 2.40 g of CuSO₄ is dissolved in 8.19 × 10² mL of 0.310 M NH₃, calculate the concentrations of the following species at equilibrium.

Cu²⁺

NH₃

Cu(NH₃)₄²⁺

Answer 1

$[Cu^{2+} ]=1.99×10^{-12} M$

$[NH3] =0.2896M$

$[Cu(NH_3)_4^{2+} ]=0.0151M$