Question

25 ° C. An aqueous solution of iodine containing 0.0516 g liter at temperature 4.412 g /liter containing CCL, is in equilibrium with the solution. 25° C If the solubility of iodine in water at temperature is 0.34 g /liter, multiply its solubility in ccl4

Answer 1

Solution:

First we find the value of K:

K = $\dfrac{C_{CCl_4}}{C_{H_2O}}$ = $\frac{4.412}{0.0516}$ = 85.5

To find the solubility of iodine in CCl₄ we should use a distribution law:

$\dfrac{Solubility \ of \ iodine \ in \ CCl_4}{Solubility \ of \ iodine \ in \ water}=85.5$

Solubility of iodine in CCl₄ = 85.5 $\times$ 0.34 = 29.07 g / L.

Answer: 29.07 g / L.