Question

The rate of formation of a dimer in a second order reaction is 7.5 × 10−3 mol L−1s−1 at 0.05 mol L−1 monomer concentration. Calculate the rate constant.

Answer 1

Let us consider the dimensation of a monomer M

2M → (M)2

Rate = k [M]²

[M] = 0.05 mol L-1

Rate = 7.5 x 10^-3 mol L-1 s

k=Rate/M²

k=(7.5 x 10^-3 mol L-1 s)/0.05²

Ans = 3 mol-1 Ls-1