Answer to Question #173438 in Physical Chemistry for Vikram

Question

The enthalpy of formation of NH₃ as per the following reaction is -46.11 kj/ mol at 298 k.

Answer 1

2NH₃(g) → N₂(g) + 3H₂(g)

The enthalpy of formation of ammonia describes the following thermochemical equation: <br>

1/2 N2 + 3/2 H2 > 2NH3

To get the enthalpy change for the given reaction, we need to reverse it and then multiply it by 2

∆H = 2( 46.11)

= 92.22 kJ