"m_{Fe}=59.5mol_{CO}\\times\\frac{2mol_{Fe}}{3mol_{CO}}\\times\\frac{55.85g_{Fe}}{1mol_{Fe}}=2.22\\cdot10^3g"
Answer: "2.22\\cdot10^3g"
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment