Answer to Question #169607 in Physical Chemistry for Ulysses

Question

The volume V of a liquid is given by

V = Vo (a + bT + CT2)

Where Vo is the volume of liquid at 298 K, a = 0.85, b = 4.2 x10-4 /K and c = 1.67 x 10-6 /K2. Determine dV/dT for the liquid at 350 K in terms of Vo.

Answer 1

differentiate given eqaution with respect to temperature.

dv/dT = 0+b + 2T

dv/dT = 4.2 x10-4 /K + 2(1.67 x 10-6 /K2)

dv/dT = 4.23 * 10^-4