Calculate the entropy change in the evaporation of 1 mole of water at 100 degree celcius .latent heat of evaporation of water is 9,650 Cal's per mole.
As we know,
□S = □H/T
= 9650/373
= 25.9 Cal/mole-K
Entropy change = [25.9] Cal/mol-K
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment