Question #16841
A 46 kg sample of water absorbs 354 kj of heat. If the water was initially at 21.1 C, what is its final temperature?
Expert's answer
q = mc delta t
m = 46 000 g
c = 4.186
q = 354 000 j
delta t = q/mc = 354000/(46000*4.186) = 1.84
finel t = 21.1 + 1.84 = 22.94 C
m = 46 000 g
c = 4.186
q = 354 000 j
delta t = q/mc = 354000/(46000*4.186) = 1.84
finel t = 21.1 + 1.84 = 22.94 C
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#340153 on Dec 2023
#340153 on Dec 2023