Answer to Question #164979 in Physical Chemistry for Eyitayo

Question

Bisola finds that the air trapped in a tube occupies 24.8cm3 at 1.14atm. By adding mercury to the tube, she increases the pressure of the trapped air to 2.68 atm. Assuming constant temperature, what is the new volume of air (in L)?

Answer 1

Using Boyle's law,

P₁V₁ = P₂V₂

1.14 × 24.8 = 2.68 × V₁

V₁ = 10.6 mL

V₁ = [0.0106] L