Question #163958

Eigenvalue of the total energy operator partical box


1
Expert's answer
2021-02-22T05:46:57-0500

As a simple example, we will solve the 1D Particle in a Box problem. That is a particle confined to a region 0<x<a

We can do this with the (unphysical) potential which is zero within those limits and +\infin outside the limits.

V(x)={00<x<aelsewhereV(x)= \begin{cases} 0 &\text 0<x<a \\ \infin &\text{elsewhere} \end{cases}

Because of the infinite potential, this problem has very unusual boundary conditions. (Normally we will require continuity of the wave function and its first derivative.) The wave function must be zero at x=0 and x=a since it must be continuous and it is zero in the region of infinite potential. The first derivative does not need to be continuous at the boundary (unlike other problems), because of the infinite discontinuity in the potential.

The time-independent Schrödinger equation (also called the energy eigenvalue equation) is

Huj=EjujHu_j=E_ju_j

with the Hamiltonian (inside the box) H=h22md2dx2H=\frac{h^2}{2m}\frac{d^2}{dx^2}

Our solutions will have uj=0u_j=0 outside the box.


The solution inside the box could be written as uj=eikxu_j=e^{ikx} where k can be positive or negative.


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