Question

A monoatomic gas ideal gas at 300k has a volume of 15 liter at a pressure 15 atm

Answer 1

Using ideal gas equation,

$PV= nRT$

Where, P = pressure = 15 atm

V = Volume = 15 L

T = Temperature = 300 K

R = Gas constant = 0.0821 atm-L/mol-K

n = number of moles

Now,

15 × 15 = n×0.0821×300

n = 9.14 mol

So, moles =[ 9.14] mol