A 0.2025 g sample consisting of only BaCl2
and KCl required 20.25 mL of 0.1200M AgNO3 solution for the quantitative precipitation of chloride.Calculate the %Ba and %K in the sample
Let y g of Kcl and ( 0.2 - y ) g of BaCl2 .
y / 74.55 + ( 0.2 - y ) × 2 / 208.23
= 20.25 × 0.12 / 1000.
Then we can find y .
Then % of Kcl = y × 100 / 0.2025
Then % of Bacl2 = ( 0.2025 -y ) × 100 / 0.2025
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