Answer to Question #161457 in Physical Chemistry for des

Question #161457

How many grams of MnO4 are required to obtain 0.028 moles?

Expert's answer

Molar mass of MnO₄ = 55 + 4×16

= 119 g

Mole (n) = 0.028 mol

Mass = n × molar mass

= 0.028 × 119

= 3.33 g

Mass of MnO₄ = [3.33] grams

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