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Answer to Question #161457 in Physical Chemistry for des
Question #161457
How many grams of MnO4 are required to obtain 0.028 moles?
Expert's answer
Molar mass of MnO4 = 55 + 4×16
= 119 g
Mole (n) = 0.028 mol
Mass = n × molar mass
= 0.028 × 119
= 3.33 g
Mass of MnO4 = [3.33] grams
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