a column of mercury has an inside diameter of 1/2 cm and is 10 ft tall. what is the down ward force in newtons, atmospheres and torr for this column of mercury
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Expert's answer
2012-10-02T07:15:12-0400
1 m = 3.28 ft 10 ft = 304.88 cm3
v = 3.14 * 1/2/2 * 1/2/2 * 304.88 = 60 cm3 density = 1,3520 g/cm3
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