An environmental chemist needs a carbonate buffer of pH 10.0 to study the effects of the acid rain on limestone-rich soils. How many grams of Na2CO3 must she add to 1.5L of freshly prepared 0.20M NaHCO3 to make the buffer? ka of HCO3- is 4.7 x 10-11.
pH= 10.0
[NaHCO3] = 0.20M
Ka= 4.7 x 10-11
pKa= -log Ka
pKa= -log (4.7 x 10-11) = 10.33
Using Henderson Hasselbalch equation:
pH= pKa + log[Na2CO3]/[NaHCO3]
10.0 = 10.33 + log [Na2CO3]/0.20
Log[Na2CO3]/0.20 = 10.0 - 10.33 = -0.33
[Na2CO3]/0.20 = 10-0.33
[Na2CO3] = 0.20 x 0.47 = 0.094M
Moles of Na2CO3= C x V
= 0.094M x 1.5L
= 0.141mole
Molar mass of Na2CO3= 106gmol-1
Mass= mole x molar mass
= 0.141 x 106 = 14.95g
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