Answer to Question #156389 in Physical Chemistry for Isaac

Question

the volume of air bubble at the bottom of a lake when the pressure is (3p/4)atm is (3v/8)cm³,what will be the product of the volume of the air bubbles at the surface of the lake of the pressure is 2/3 of the original value and the pressure is reduced by 3/8 of the original value at constant temperature?

Answer 1

The question is two in one

I. P₁= 3p/4

V₁= 3v/8

P₂= 2/3P₁ = 2/3 x 3p/4 = p/2

V₂₌ ?

From boyle's law

P₁V₁ = P₂V₂

V₂ = P₁V₁/P₂ = 3p/4 x 3v/8 ÷ p/2

= 9v/16

II. If P₂= 3/8P₁ = 3/8 x 3p/4 = 9p/32

V₂= 3p/4 x 3v/8 x 32/9p = v