Answer to Question #156312 in Physical Chemistry for tayba

Question

How much electrical energy is required to generate 1.000L of H, at 25°C and 1.00 atm pressure by the electrolysis of water?

Answer 1

Pv = nRT .

1 × 1 = n × 0.0821 × 298 .

n = 1 / 0.0821 × 298 .

n = 0.0408 mol. Mol of H₂ gas .

For

2 H⁺ + 2e ----------- H₂.

For 1mol of H₂ 2mol of e required .

So , mol of electron required = 2n = 2 × 0.04

= 0.08 mol of electron .

Charge = ( 0.08 × 96500 ) Coulomb.

= 7720 C .