Answer to Question #154262 in Physical Chemistry for TANIA

Question

A student has carried out a moving boundary experiment using K2SO4 as an electrolyte. The data obtained was tabulated below:

Cation velocity: 11.43 mms-1

Cross-sectional area of tube: 28.56 mm2

Transference number of cation: 0.593

Anion concentration: 0.025 mol dm-3

Calculate the current flow for the boundary moves as far as 45 mm.

Answer 1

t₊ (tansference number of cation) = $\frac{z_+*c*L*A*F}{Q}$

$Q=\frac{z_+*c*L*A*F}{t_+}$

z₊ = 1 (charge of cation)

c(K⁺) = 0.025*2 = 0.05 mol/dm³ = 0.00005 mol/cm³

L = 45 mm = 4.5 cm

A (cross-sectional area of tube) = 28.56 mm² = 0.2856 cm²

F = 96500 C/mol

t₊ = 0.593

$Q=\frac{1*0.00005*4.5*0.2856*96500}{0.593}=10.46$ C