Mn=∑NiMi∑Ni=5∗1+10∗2+10∗50+10∗10+5∗205+10+10+10+5=18.125M_n=\frac{\sum N_iM_i}{\sum N_i}=\frac{5*1+10*2+10*50+10*10+5*20}{5+10+10+10+5}=18.125Mn=∑Ni∑NiMi=5+10+10+10+55∗1+10∗2+10∗50+10∗10+5∗20=18.125 kg/mol
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