C2H4(g) + 3O2(g) → 2CO2(g) + 2H2O(g) ΔHrxn = ? kJ
C2H4 + 3O2 ---> 2CO2 + 2 H2O
From Appendix table
∆H°f C2H4 = 52.3Kj/mol
∆H°fCO2= -393.5Kj/mol
∆H°f H2O(g) = -241.8Kj/mol
∆H°rxn= ∆H°products - ∆H°reactants
∆H°rxn = [2(-393.5)+2(-241.8)] - [52.3]
∆H°rxn = -1322.9KJ/mol
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