Solution.
"t(1\/2) = \\frac{ln(2)}{k}"
"k = \\frac{ln(2)}{t(1\/2)}"
"k = \\frac{1}{t} ln(C0\/C)"
"t = \\frac{ln(\\frac{C0}{C})}{k}"
C0 = 1
C = 0.6*C0
"k = 3.38 \\times 10^{-5} sec"
t = 15113 sec = 4.2 hours
Answer:
t = 4.2 hours
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