p = 690 mmHg = 91992 Pa
A(surface area) = 80cm² = 80/(100*100) = 0.008 m²
l = 200cm = 2 m
W (work) = p*A*l = 91992*0.008*2 = 1472 J
Q = 4kJ = 4000 J
"\\Delta"U (change in internal energy) = Q-W = 4000-1472 = 2528 J
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