Question

The total volume of seawater is 1.5 x 1021 L. Assume that seawater contains 3.1 percent sodium chloride by mass and that its density is 1.03 g/mL. Calculate the total mass of sodium chloride in kilograms and in tons. (1 ton = 2000 lb; 1 lb = 453.6 g.)

Answer 1

Mass of sea water = volume x density =$1.5\times10^{21}\times1030=1.545\times10^{24}Kg$

Sodium chloride is 3.1 % of sea water

So, mass of sodium chloride sea water=$\frac{3.1}{100}\times1.545\times10^{24}=4.79\times10^ {22}$ Kg

$1 \ tons=10^3 kg$

in tonnes mass of sodium chloride = $4.79\times10^ {19}$