Answer to Question #141931 in Physical Chemistry for Raisya

Question

Calculate the change of Gibbs energy when 3.0 mol H2 mixes with 1.0 mol N2 at the same pressure with the volume of the vessel adjusted accordingly.

Answer 1

Solution.

$\chi (H2) = \frac{3}{3+1} = 0.75$

$\chi (N2) = \frac{1}{3+1} = 0.25$

n = 4 mol

$\Delta G = nRT(\chi(H2) \times ln(\chi(H2)) + \chi(N2) \times ln(\chi(N2)))$

$\Delta G = 4 \times 8.31 \times 298(0.75 \times ln(0.75) + 0.25 \times ln(0.25)) = -5570.22 J/mol$

Answer:

$\Delta G = -5570.22 J/mol$