Solution.
"\\chi (H2) = \\frac{3}{3+1} = 0.75"
"\\chi (N2) = \\frac{1}{3+1} = 0.25"
n = 4 mol
"\\Delta G = nRT(\\chi(H2) \\times ln(\\chi(H2)) + \\chi(N2) \\times ln(\\chi(N2)))"
"\\Delta G = 4 \\times 8.31 \\times 298(0.75 \\times ln(0.75) + 0.25 \\times ln(0.25)) = -5570.22 J\/mol"
Answer:
"\\Delta G = -5570.22 J\/mol"
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