Solution.
H(Temporary)=V(sample)C(EDTA)×V(EDTA)×1000
H(Temporary)=1000.02×16.8×1000=3.36mmol−equiv/L
H(Permanent)=V(sample)C1(EDTA)×V1(EDTA)−C2(EDTA)×V2(EDTA)×1000
H(Permanent)=100(0.02×16.8−0.02×10.7)×1000=1.22mmol−euiv/L
Answer:
H(Temporary) = 3.36 mmol-equiv/L
H(Permanent) = 1.22 mmol-euiv/L
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