Question

The transport number of lithium ion is 0.56 in LiBr solution at 25 degree Celsius. What is the transport number of bromide ion ? *

Answer 1

Solution.

$t(Li^+) + t(Br^-) = 1$

$t(Br^-) = 1-t(Li^+)$

$t(Br^-) = 0.44$

Answer:

$t(Br^-) = 0.44$