Answer to Question #134234 in Physical Chemistry for Supriya

Question

Calculate the entropy of mixing when 2.00 mol of H2 are mixed with 3.00 mol of N2 assuming that no chemical reaction accur between them

Answer 1

Ans.

Total mole number of hydrogen and nitrogen = (2+3)= 5 mol

Mole fraction of H₂ = 2/5

Mole fraction of N₂ = 3/5

Entropy of mixing = -5R{(2/5)ln(2/5) + (3/5)ln(3/5)} = 3.36R = 27.94J/mol·K