Question

Derived the relation between the molarity and normality of x gram of suphuric acid dissolved in 100ml of water

Answer 1

You can convert from molarity to normality using the following equation:

$Normality=Molarity\times\frac{Molecularmass}{Equivalent mass}$

For sulphuric acid $Normality=Molarity\times\frac{98}{49}=Molarity\times2$

Molarity of sulphuric acid = $\frac{chemical amount}{solutionvolume}=\frac{\frac{x}{98}}{\frac{x+100}{\rho}}$

where $\rho$ - solution dencity

Normality of sulphuric acid = $=\frac{\frac{2x}{98}}{\frac{x+100}{\rho}}$