Answer to Question #127967 in Physical Chemistry for dalia

Question

A 456 mL sample of argon gas is expanded at constant at constant pressure to 1.75 L at 55ºC. What was the original temperature of the gas in º C?

a.
-188 ºC

b.
188 º C

c.
200 F

d.
-200 F

Answer 1

V₁ / T₁ = V₂ / T₂ ........

0.456 L / T₁ = 1.75 L / 328 K.

T₁ = 0.456 × 328 / 1.75 .

T₁ = 85.467 K .