Potential well of width (L) = 0.2 × 10–6 m
For ground state n = 1,
Energy = n2h2 / 8mL2 .
So , Energy = (1 )2. (6.63*10-34)2 / 8 * ( 9.1 *10-31 ) * ( 10-6 )2 .
Energy = ( 6.63 )2 * 10-25 / 8 * ( 9.1)
Energy = 0.603 *10-25 j = 6.03 * 10-26 j . (Answer ) .
Energy = 6.03 *10 -26 / 1.6 * 10-19 = 3.76 * 10 -7 ev . ( ANSWER .) .
Comments
Leave a comment