Answer to Question #126326 in Physical Chemistry for Sonia

Question #126326

 "A water sample contains following impurities: Mg(HCO3)2 = 292 mg/L, CaCl2 = 166.5 ppm, SiO2 = 5 ppm, Calculate the volume of EDTA solution (0.1 N) required to titrate 50 mL of the water sample before boiling and after boiling-filtering. (Ans: 1.5 mL)" 


1
Expert's answer
2020-07-14T15:18:00-0400

Solution.

m(Mg(HCO3)2)=292×0.05=14.6 mgm(Mg(HCO3)2) = 292 \times 0.05 = 14.6 \ mg

m(CaCl2)=166.5×0.05=8.325 mgm(CaCl2) = 166.5 \times 0.05 = 8.325 \ mg

ν=ν(Mg(HCO3)2)+ν(CaCl2)=0.0146146+0.008325111=0.000175 mol\nu = \nu(Mg(HCO3)2) + \nu(CaCl2) = \frac{0.0146}{146} + \frac{0.008325}{111} = 0.000175 \ mol

V(EDTA)=ν×1000H=1.75 mlV(EDTA) = \frac{\nu \times 1000}{H} = 1.75 \ ml

Answer:

V(EDTA) = 1.75 ml


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