Question

Which of the following shifts the equilibrium of the following reaction to the right?A(g) + B(g) + C(g) ⇌ A(g) + BC(g)

Answer 1

$A(g) + B(g) + C(g) ⇌ A(g) + BC(g)$

In the above reaction,the number of moles of gases on the right hand side is less than that on left hand side .It means that the pressure gets lowered when reaction moves forward as $P\propto n$

Therefore,when pressure is increased in reaction mixture,by Le Chatlier principle,the reaction tend to reduce it and so the equilibrium shifts to right.

Hence by increasing pressure,the reaction equilibrium shifts in forward direction.