Answer to Question #120661 in Physical Chemistry for Pratheek

Question

Multiplying the gas volume by the increased carbon dioxide concentration and dividing by the weight and sampling duration would then calculate the carbon dioxide production rate.

Answer 1

The statement is true:

Let gas volume be $V$ and increase in $CO_2$ concentration$($ in $g/l)$ be $\triangle M$ ,then

$\triangle MV$ will be mass of $CO_2$ produced.

And $\frac{\triangle M V}{M_m}$ that is division by molecular weight will give number of moles produced .

If we divide number of moles produced by time taken that is $\frac{\triangle MV}{M_m t}$ ,it will result in moles of $CO_2$ produced per unit time OR carbon dioxide production rate.