Question

Multiplying the gas volume by the increased carbon dioxide concentration and dividing by the weight and sampling duration would then calculate the carbon dioxide production rate.

Answer 1

The statement is true:

Let gas volume be $V$ and increase in $CO_2$ concentration$($ in $g/l)$ be $\triangle M$ ,then

$\triangle MV$ will be mass of $CO_2$ produced.

And $\frac{\triangle M V}{M_m}$ that is division by molecular weight will give number of moles produced .

If we divide number of moles produced by time taken that is $\frac{\triangle MV}{M_m t}$ ,it will result in moles of $CO_2$ produced per unit time OR carbon dioxide production rate.