"pH=11.6 \n\\\\\npOH =14-11.6=2.4"
let's calculate the concentration of OH- from the pOH
"[OH^-]=4\\times10^{-3}"
now calculating the concentration of calcium ions from the Ksp of Calcium hydroxide
"[Ca^{2+}]=\\frac{K_{SP}}{[OH^-]^2}=\\frac{4\\times10^{-5}}{16\\times10^{-6}}=2.5"
similarly calculating the concentration of sulfate ions from Ksp of Calcium Sulfate
"[SO_4^{2-}]=\\frac{K_{SP}}{Ca^{2+}}=\\frac{2.5\\times10^{-5}}{2.5}=10^{-5}"
Comments
Leave a comment