Let the molar mass of the compound be xxx
mass of 4 atoms of oxygen = 4×\times× 16=64 g
64 g of this oxygen accounts for 43.8 % of the total weight
43.8% of x=64g43.8 \% \ of\ x = 64 g43.8% of x=64g
x=64×10043.8=146.11gx=\frac{64\times100}{43.8 }=146.11 gx=43.864×100=146.11g
molar mass of the compound is 146.11 g
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