Solution.
CH3COOH+KBr=CH3COOK+HBrCH3COOH + KBr = CH3COOK + HBrCH3COOH+KBr=CH3COOK+HBr
λ0(CH3COOK)=λ0(CH3COOH)+λ0(KBr)−λ0(HBr)\lambda^0 (CH3COOK) = \lambda^0 (CH3COOH) + \lambda^0 (KBr) - \lambda^0 (HBr)λ0(CH3COOK)=λ0(CH3COOH)+λ0(KBr)−λ0(HBr)
λ0(CH3COOK)=391+106−385=112 S cm2 mol−1\lambda^0 (CH3COOK) = 391 + 106 - 385 = 112 \ S \ cm2 \ mol-1λ0(CH3COOK)=391+106−385=112 S cm2 mol−1
Answer:
λ0(CH3COOK)=112 S cm2 mol−1\lambda^0 (CH3COOK) = 112 \ S \ cm2 \ mol-1λ0(CH3COOK)=112 S cm2 mol−1
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