Solution.
1.
AB2=A2++2B−
C(AB2)=Solubility=X
[A2+]=X
[B−]=2×X
Ks=[A2+]×[B−]2=X×(2×X)2=4×X3
2.
A2B=2A++B2−
C(A2B)=Solubility=X
[A+]=2×X
[B2−]=X
Ks=[A+]2×[B2−]=(2×X)2×X=4×X3
Answer:
1.
[A2+]=X
[B−]=2×X
Ks=[A2+]×[B−]2=X×(2×X)2=4×X3
2.
[A+]=2×X
[B2−]=X
Ks=[A+]2×[B2−]=(2×X)2×X=4×X3
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