Question #117178

Define solubility product constant and derive the relationships between solubility

and solubility product constants for salts of AB2, A2B types.

Expert's answer

Solution.

1.

AB2=A2++2B−AB2 = A^{2+} + 2B^-

C(AB2)=Solubility=XC(AB2) = Solubility = X

[A2+]=X[A^{2+}] = X

[B−]=2×X[B^-] = 2 \times X

Ks=[A2+]×[B−]2=X×(2×X)2=4×X3Ks = [A^{2+}] \times [B^-]^2 = X \times (2\times X)^2 = 4 \times X^3

2.

A2B=2A++B2−A2B = 2A^+ + B^{2-}

C(A2B)=Solubility=XC(A2B) = Solubility = X

[A+]=2×X[A^+] = 2 \times X

[B2−]=X[B^{2-}] = X

Ks=[A+]2×[B2−]=(2×X)2×X=4×X3Ks = [A^+]^2 \times [B^{2-}] = (2 \times X)^2 \times X = 4 \times X^3

Answer:

1.

[A2+]=X[A^{2+}] = X

[B−]=2×X[B^-] = 2 \times X

Ks=[A2+]×[B−]2=X×(2×X)2=4×X3Ks = [A^{2+}] \times [B^-]^2 = X \times (2\times X)^2 = 4 \times X^3

2.

[A+]=2×X[A^+] = 2 \times X

[B2−]=X[B^{2-}] = X

Ks=[A+]2×[B2−]=(2×X)2×X=4×X3Ks = [A^+]^2 \times [B^{2-}] = (2 \times X)^2 \times X = 4 \times X^3


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