Question

Calculate the molar solubility of BaSO4 in water and. (Ksp = 1.1 X 10-10)

Answer 1

$BaSO 4 ​ (s)⟶Ba^ {2+} (aq)+SO 4^ {2−} ​ (aq)\\ ∴K sp ​ =[Ba^{ 2+} ][SO_ 4^{ 2−} ​ ]=x\\ Then, 1.1×10 ^{−10} =x×x;\\x ^2 =1.1×10 ^{−10} or\\x=1.05×10 ^{−5}\\ Then, solubility\ of\ BaSO _4 ​ \ in\ pure\ water\ is \ 1.05×10 ^{−5} .$