Solution.
1.
pH=−lg[H+]pH = -lg[H^+]pH=−lg[H+]
[H+]=10−pH[H^+] = 10^{-pH}[H+]=10−pH
[H+]=6.31×10−6 M[H^+] = 6.31 \times 10^{-6} \ M[H+]=6.31×10−6 M
2.
pOH=−lg[OH−]pOH = -lg[OH^-]pOH=−lg[OH−]
pOH = 8.43
pH+pOH=14pH + pOH = 14pH+pOH=14
pH=14−pOHpH = 14 - pOHpH=14−pOH
pH = 5.57
[H+]=2.69×10−6 M[H^+] = 2.69 \times 10^{-6} \ M[H+]=2.69×10−6 M
Answer:
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