Question

Calculate the standard EMF of a cell which involves the following cell reaction
Zn+ 2Ag+ = Zn^2+ + 2Ag
Given that E0 Zn, Zn^2+ = 0.76 V and E0 Ag, Ag+ = -0.80 V

Answer 1

Solution.

If we look at this reaction, then zinc will be oxidized (zinc is the anode), and silver will be reduced (silver is the cathode). Then the equation for finding the EMF of a galvanic pair is as follows:

$EMF = E(Ag^+/Ag) - E(Zn^{2+}/Zn)$

$EMF = -(-0.80) - (-0.76) = 1.56 \ V$

Answer:

EMF = 1.56 V