1.CH4 + O2 --> CO2+H2O;
∆H=802.3 kJ/mol
p=768 mm Hg=102,4 kPa
T=18.6 oC=273+18.6=291.6 K
n(CH4)=(p*V)/(R*T)=102.4*1.63*(10^3)/(8.314*296.7)=67.66 mol
Q=∆H*n=802.3*67.66=54283.62 kJ
2.C(H2O)=4.2 kJ/(kg*oC)
C=Q/(m*∆T);
m(H2O)=Q/(C*∆T)=54283.62/(4.2*51.3)=252 kg
L(H2O)=252 L
Answer: 1. 54283.62 kJ
2.252 L
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