Question

Calculate the amount of heat supplied to a carnot cycle working between 368K and 288K if maximum obtain is 895J.

Answer 1

maximum efficiency in carnot cycle =$\frac{T_2-T_1}{T_2}=\frac{368-288}{368}=0.217$

Heat obtained = efficiency$\times$heat supplied

895=0.217*heat supplied

heat supplied = 4124 J