Using ideal gas law equation,
PV=nRT
V=224ml=0.224L, P=1atm, R=0.082 and T=273K
1atm×0.224L=n×0.082Latm mol
−1
K
−1
×273K
n=0.01 mol
0.01 mol of gas contains 1g.
1mol of gas =100g
Therefore, 6.022×10
23
×3 atoms=100 g
Mass of one atom =5.53×10
−23
g
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