Answer to Question #112016 in Physical Chemistry for DEEPAK SINGH

Question

19.5g CH3COOH is dissolved in 500g of water the depression in the freezing point observed is 1.0k calculate van't hoff factor and dissociation constant of the acid.

Answer 1

‎ΔT_freezing=iC_mK=1K

C_m=m( CH3COOH)/(Mr( CH3COOH)*m(H2O))=19.5/(60*0.5)=0.65 mol/kg

i=1/(1.86*0.65)=0.83;

K_d=(1*0.5/1.86)/(19.5/60)=0.83

Answer:i=0.83;

Kd=0.83