Question

19.5g CH3COOH is dissolved in 500g of water the depression in the freezing point observed is 1.0k calculate van't hoff factor and dissociation constant of the acid.

Answer 1

‎ΔT_freezing=iC_mK=1K

C_m=m( CH3COOH)/(Mr( CH3COOH)*m(H2O))=19.5/(60*0.5)=0.65 mol/kg

i=1/(1.86*0.65)=0.83;

K_d=(1*0.5/1.86)/(19.5/60)=0.83

Answer:i=0.83;

Kd=0.83