Let the reaction be
A→kproduct Initial amount of of A be A°
Rate law eqn will be
dtdA=−kA Seperating variables
We get
dA=−kAdt Integrating it From A° to A
We get
[lnAA°]A=−ktlnA−lnA°=−ktlnA°A=−ktA=A°e−kt This is the integrated rate law for first order reaction.
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