Question #110627
derive integrated rate law for the first order reaction.
1
Expert's answer
2020-04-20T15:08:40-0400

Let the reaction be


AkproductA\overset{k}{\to} product

Initial amount of of A be A°A_°

Rate law eqn will be


dAdt=kA\frac{dA}{dt}= -kA

Seperating variables

We get


dA=kAdtdA= -kAdt

Integrating it From A° to AFrom \ A_°\ to \ A

We get


[lnA]AA°=ktlnAlnA°=ktlnAA°=ktA=A°ekt[lnA\underset{A_°}{\overset{A}{]}}= -kt\\lnA-lnA_°= -kt\\ln\frac{A}{A_°}= -kt\\A= A_°e^{-kt}

This is the integrated rate law for first order reaction.


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